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Var $(4X+3)$ is

\[\begin{array}{1 1}(1)7&(2)16 \;var(X)\\(3)19&(4)0\end{array}\]

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1 Answer

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$Var (4X+3) =Var (4X)+Var (3)$
$\qquad= 4^2 Var (X) +0$
$\qquad= 16 Var X$
Hence 2 is the correct answer.
answered May 23, 2014 by meena.p
 

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