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If $n(A\times B)=8, $ then how many possible values are there for $n(A)?$

(A) 1

(B) 2

(C) 3

(D) 4

1 Answer

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  • $n(A\times B)=n(A).n(B)$
$8=1\times 8,\:\:2\times 4,\:\:4\times 2,\:\:8\times 1$
$\Rightarrow n(A)=1,2,4 \:or\:8$
There are 4 possible values of $n(A)$
answered May 30, 2013 by rvidyagovindarajan_1
 
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