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If $f(x)$ is a p.d.f of a normal variate $x$ and $X\sim N(\mu,\sigma^{2})$ then $\int\limits_{-\infty}^{\mu}f(x)dx $ is

\[\begin{array}{1 1}(1)undefined&(2)1\\(3).5&(4)-.5\end{array}\]

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$\int\limits_{-\infty}^{\mu}f(x)dx = \int\limits_{-\infty}^{0}f(x)dx =0.5$
Hence 3 is the correct answer.
answered May 23, 2014 by meena.p
 

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