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The equation of state of some gases can be expressed as $ \bigg(p+\large\frac{a}{v^2}\bigg)$$(v-b)=RT$ Here $p$ is pressure, $v$ is volume , $a,b,R$ are constants. The dimensions of $ 'a'$ are

\[(a)\;ML^5T^{-2}\quad (b)\;ML^{-1}T^{-2}\quad (c)\;M^0L^3T^0\quad (d)\;M^0L^6T^0\]

1 Answer

By principle of dimensional homogeneity
=>$ a=pv^2=[ML^{-1}T^{-2}][L^3]^2$
Hence the dimensions of  $'a'$ are $ML^5T^{-2}$ 
Hence a is the correct answer. 


answered Jun 13, 2013 by meena.p
edited Jan 9, 2014 by meena.p

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