# The equation of state of some gases can be expressed as $\bigg(p+\large\frac{a}{v^2}\bigg)$$(v-b)=RT Here p is pressure, v is volume , a,b,R are constants. The dimensions of 'a' are $(a)\;ML^5T^{-2}\quad (b)\;ML^{-1}T^{-2}\quad (c)\;M^0L^3T^0\quad (d)\;M^0L^6T^0$ ## 1 Answer By principle of dimensional homogeneity \large\frac{a}{v^2}$$=p$
=>$a=pv^2=[ML^{-1}T^{-2}][L^3]^2$
$\qquad=ML^5T^{-2}$
Hence the dimensions of  $'a'$ are $ML^5T^{-2}$
Hence a is the correct answer.

edited Jan 9, 2014 by meena.p