logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Units and Measurement
0 votes

The equation of state of some gases can be expressed as $ \bigg(p+\large\frac{a}{v^2}\bigg)$$(v-b)=RT$ Here $p$ is pressure, $v$ is volume , $a,b,R$ are constants. The dimensions of $ 'a'$ are

\[(a)\;ML^5T^{-2}\quad (b)\;ML^{-1}T^{-2}\quad (c)\;M^0L^3T^0\quad (d)\;M^0L^6T^0\]

Can you answer this question?
 
 

1 Answer

0 votes
 
By principle of dimensional homogeneity
$\large\frac{a}{v^2}$$=p$
=>$ a=pv^2=[ML^{-1}T^{-2}][L^3]^2$
$\qquad=ML^5T^{-2}$
Hence the dimensions of  $'a'$ are $ML^5T^{-2}$ 
Hence a is the correct answer. 

 

answered Jun 13, 2013 by meena.p
edited Jan 9, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...