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Units and Measurement
If $C$ is capacity and $V$ is the potential across the condenser, what will be the dimensional representation of $\large\frac{1}{2}$$CV^2$
\[(a)\;ML^2T^{-2}A^{-2}\quad (b)\;ML^{-2}T^{2}\quad (c)\;ML^2T^{-3}A^{-2}\quad (D)\;ML^2T^{-2}\]
jeemain
physics
class11
ch2
units-and-measurement
q2
easy
dimensional-formulae-and-analysis
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asked
Jun 15, 2013
by
meena.p
retagged
Jul 11, 2014
by
balaji.thirumalai
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1 Answer
$\large\frac{1}{2}$$CV^2=\large\frac{1}{2}\;\frac{charge}{potential} $$\times (potential)^2$
$\qquad\quad=\large\frac{1}{2}\;$${charge} \times \large\frac{work}{charge}$
$\qquad\quad=\large\frac{1}{2} $$work$
It has same unit as work.
Hence D is the correct answer.
answered
Jun 15, 2013
by
meena.p
edited
Jan 9, 2014
by
meena.p
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