# $E.m,J$ and $G$ denote energy,mass angular momentum and gravitational constant respectively then the dimension of $\large\frac{EJ^2}{m^5G^2}$ are

$(a)\;Angle\quad (b)\;Length\quad (c)\;Mass\quad (d)\;Time$

$\large\frac{EJ^2}{m^5G^2}=\frac{[ML^2T^{-2}][ML^2T^{-1}]^2}{[M^5][M^{-1}L^3T^{-2}]^2}$
$\qquad\quad=[M^0L^0T^0]$
The dimension of $\large\frac{EJ^2}{m^5G^2}$ are Angle
Hence a is the correct answer.

edited Jan 9, 2014 by meena.p