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# $E.m,J$ and $G$ denote energy,mass angular momentum and gravitational constant respectively then the dimension of $\large\frac{EJ^2}{m^5G^2}$ are

$(a)\;Angle\quad (b)\;Length\quad (c)\;Mass\quad (d)\;Time$

Can you answer this question?

$\large\frac{EJ^2}{m^5G^2}=\frac{[ML^2T^{-2}][ML^2T^{-1}]^2}{[M^5][M^{-1}L^3T^{-2}]^2}$
$\qquad\quad=[M^0L^0T^0]$
The dimension of $\large\frac{EJ^2}{m^5G^2}$ are Angle
Hence a is the correct answer.

answered Jun 16, 2013 by
edited Jan 9, 2014 by meena.p