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$E.m,J$ and $ G$ denote energy,mass angular momentum and gravitational constant respectively then the dimension of $\large\frac{EJ^2}{m^5G^2}$ are
\[(a)\;Angle\quad (b)\;Length\quad (c)\;Mass\quad (d)\;Time\]
jeemain
physics
class11
ch2
units-and-measurement
q5
easy
dimensional-formulae-and-analysis
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asked
Jun 16, 2013
by
meena.p
retagged
Jul 11, 2014
by
balaji.thirumalai
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1 Answer
$\large\frac{EJ^2}{m^5G^2}=\frac{[ML^2T^{-2}][ML^2T^{-1}]^2}{[M^5][M^{-1}L^3T^{-2}]^2}$
$\qquad\quad=[M^0L^0T^0]$
The dimension of $\large\frac{EJ^2}{m^5G^2}$ are Angle
Hence a is the correct answer.
answered
Jun 16, 2013
by
meena.p
edited
Jan 9, 2014
by
meena.p
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