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The unit of L / R is (L=inductance and R=resistance)

\[(a)\;sec \quad (b)\;sec ^{-1}\quad (c)\;volt \quad (d)\;ampere\]

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1 Answer

$L/R$ is the time constant
The unit of $L/R$ is sec
Hence a is the correct answer. 


answered Jun 17, 2013 by meena.p
edited Jan 9, 2014 by meena.p