Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Units and Measurement
0 votes

The position $x$ of a particle at time $t$ is given by $x=\large\frac{v_0}{a} $$(1-e^{-at})$ where $v_0$ is constant and $a >0$ find the dimensions of $v_0$ and $a$

\[(a)\;M^0LT^{-1}\;and\;T^{-1} \quad (b)\;M^0LT^0\;and \;T^{-1}\quad (c)\;M^0LT^{-1}\;and\;LT^{-2} \quad (d)\;M^0LT^{-1}\;and\;T\]

Can you answer this question?

1 Answer

0 votes
$a \times t$ is dimensionless quantity
also $x=\large\frac{v_0}{a}$ and $v_0=x \;a$
Hence the dimensions of $v_0=M^0LT^{-1}\;and\; a=\;T^{-1}$
Hence a is the correct answer.
answered Jun 17, 2013 by meena.p
edited May 29, 2014 by lmohan717

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App