Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Units and Measurement
0 votes

The value of Kinetic energy $K$ and potential energy $V$ are measured as follows $K=100.0 \pm 2.0\; I \quad V=200.0 \pm 1.0\; I$. What is the percentage error in measurement of mechanical energy ?

\[(a)\;2.5 \% \quad (b)\;1 \%\quad (c)\;0.5 \%\quad (d)\;1.5 \%\]

Can you answer this question?

1 Answer

0 votes
$ME=K+V=E+\Delta E$
$ME=K+V=300 \pm 3$
$\%$ error in $ME=\large\frac{\Delta E}{E}$$\times 100$
$=\large\frac{3}{300} $$\times 100$
$=1 \%$
Hence b is the correct answer.


answered Jun 17, 2013 by meena.p
edited Mar 14, 2014 by thagee.vedartham

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App