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# Volt is equivalent to

$(a)\;\frac{Ergs}{centimeter} \quad (b)\;\frac{Newton}{coulomb} \quad (c)\;\frac{Joules}{coulomb}\quad (d)\;\frac{Erg}{Ampere}$

$V(Potential)=\large\frac{Work\;done}{charge}$
$=\large\frac{Joules}{coulomb}$
Hence volt is equivalent to $\large\frac{Joules}{coulomb}$
Hence c is the correct answer.

edited Jan 9, 2014 by meena.p