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Dimensional formula for the product of two physical quantities $P$ and $Q$ is $ ML^2T^{-2}$. The dimensional formula for $\large \frac{P}{Q}$ is $ML^0T^{-2}$. $P$ and $Q$ are

\[(a)\;Force,velocity\quad (b)\;Momentum \; displacement\quad (c)\;Force,displacement (d)\;work\;velocity\]

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$P \times Q= ML^2T^{-2}= \;work\;done$ =Force . displacement
$\large\frac{P}{Q}$$=MT^{-2}=\large \frac{Force}{displacement}$
P and Q are Force and displacement
Hence c is the correct answer.


answered Jun 17, 2013 by meena.p
edited Jan 9, 2014 by meena.p

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