# If fundamental units of mass, length and time are each doubled, what happens to unit of energy

$(a)\;halved \quad (b)\;tripled \quad (c)\;doubled \quad (d)\;becomes \;4\;times$

$[E]=[ML^2T^{-2}]$
$[E']=[2M4L^2T^{-2}/4]$
$\qquad=2[E]$
Hence c is the correct answer.

answered Jun 18, 2013 by
edited Jul 11, 2014