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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Units and Measurement
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If pressure $P$, velocity $V$ and $T$ are taken as fundamental physical quantities the dimensional formula of force is

\[(a)\;PV^2T^2 \quad (b)\;P^{-1}V^2T^{-2} \quad (c)\;PVT^2 \quad (d)\;P^{-1}VT^2\]

Can you answer this question?
 
 

1 Answer

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$Force=P^xV^yT^z$
$[MLT^{-2}]=[MLT^{-2}L^{-2}]^x[LT^{-1}]^y[T]^z$
Solving we get,
$x=1$
$y=2$
$z=2$
 

 

answered Jun 18, 2013 by meena.p
edited Jun 19, 2013 by meena.p
 

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