Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Units and Measurement
0 votes

The caesium clock are capable of measuring time with an accuracy of $1$ part in $10^{11}$. If two such clock run for $100$ years, find the difference in time shown by the clock

\[(a)\;0.032s \quad (b)\;0.01 s \quad (c)\;0.0032  s\quad (d)\;0.001s\]

Can you answer this question?

1 Answer

0 votes
Possible fractional error=$\large\frac{1}{10^{11}}$
$100\; years=100 \times 364 \times 86400$ seconds
$\qquad\qquad=3.2 \times 10^9s$
Difference in time $=\large\frac{1}{10^{11}}$$\times 3.2 \times 10^9$
Hence a is the correct answer.


answered Jun 18, 2013 by meena.p
edited Jan 9, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App