\[\begin{array}{1 1}(a)\;A\;is\;\frac{1}{second}\;B\;is \;meter \\(b)\;A\;is\;\frac{1}{second}\;B\;is \;\frac{1}{kilogram} \\ (c)\;A\;is\;second\;B\;is \;meter \\ (d)\;A\;is\;second \;B\;is \frac{1}{kilogram}\end{array}\]

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$V=Axe^{Bm}-\large\frac{c^2}{v_0}$

$meter/second=A(meters) e^{B(\large kilogram)}+c^2/(meter/second)$

$\qquad\qquad\qquad=A(meters)e^{(\large unitless)}-(meters)/second$

Therefore $A=\large\frac{1}{second};$$\quad B=\large\frac{1}{kilogram};$$\quad C=\large\frac{meter}{second}$

Hence B is the correct answer.

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