# If P(A) = $\large \frac{1}{2}$ and P(B) = 0, then P$\large(\frac{A}{B})$ is?

(A) Zero (B) 1/2 (C) not defined (D) 1

Toolbox:
• Given P(E), P(F), P(E $\cap$ F), P(E/F) $= \large \frac{P(E \;\cap \;F)}{P(F)}$
P(A/B) $= \large \frac{P(A \;\cap \;B)}{P(B)}$. In this case the denominator is zero there is no solution.
Solution: (C) Not defined.