\[(a)\;4 \Omega \pm 16.25 \% \quad (b)\;(4 \pm 0.7)\Omega \quad (c)\;4 \Omega \pm 0.7\%\quad (d)\;4 \Omega \pm 7\%\]

Resistance $=\large\frac{8}{2}$$=4 \Omega$

% error in R = % error in V + % error in I.

$\qquad\qquad\qquad=\large\frac{.5}{8} $$\times 100+ \large\frac{.2}{2} $$\times 100$

$\qquad\qquad\qquad=16.25\%$

Hence the $\%$ of error is $16.25 \%$

Therefore, the correct answer is $(A)\;4 \Omega \pm 16.25 \% $

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