Browse Questions

# Find the area of the region bounded by $y^2 = 9x,\; x = 2,\; x = 4$ and the $x$ - axis in the first quadrant.

$\begin{array}{1 1} 16-4\sqrt 2sq.units. \\8-4\sqrt 2sq.units. \\ 16-2\sqrt 2sq.units. \\ 8-4\sqrt 3sq.units.\end{array}$

Toolbox:
• To find the area bounded by the curve y=f(x),x-axis and the ordinate x=a,x=b then the required area is given by,
• $A=\int_a^b y\;dx=\int_a^b f(x)\;dx.$
Given curve is $y^2=9x\Rightarrow y=3\sqrt x.$