# Suppose X has a binomial distribution $B\; \large($$6, \large\frac{1}{2})$. What is the most likely outcome and for what value of X, where x = 0, 1, 2, 3, 4, 5, 6?
$\begin{array}{1 1} X = 3, \; P (X=3) = \large\frac{20}{64} \\ X = 3, \; P (X=4) = \large\frac{15}{64} \\ X = 3, \; P (X=4) = \large\frac{25}{64} \\ X = 3, \; P (X=3) = \large\frac{15}{64} \end{array}$