Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Straight Line
0 votes

The position x of a particle varies with time as $x=at^2-bt^3$. The acceleration of the particle will be zero at time t equal to

\[(a)\;\frac{a}{b}\quad (b)\;\frac{2a}{3b} \quad (c)\;\frac{a}{3b} \quad (d)\;zero\]

Can you answer this question?

1 Answer

0 votes
Hence c is the correct answer


answered Jun 21, 2013 by meena.p
edited Jan 24, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App