$\begin{array}{1 1} (a) go\;on\;decreasing \;with \;time \\(b)be\; independent\; of\; \alpha\;and\; \beta \\(c) drop\;of\;zero\;when\;\alpha=\beta \\(d)\;go\;on\;increasing\;with\;time \end{array} $

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Answer: go on increasing with time.

Given $x=ae^{-\alpha t}+be^{\beta t}$

Velocity = displacement / time = $v=\large\frac{dx}{dt}$$=-a\; \alpha e^{-\alpha t}+b \beta e^{\beta t}$

As you can see, velocity is dependent of $\alpha$ and $\beta$, and does not drop to zero when $\alpha = \beta$

Now as t increases, $-a\;\alpha e^{-\alpha}$ decreases and $b\;\beta e^{\beta}$ increases $\rightarrow$ velocity goes on increasing with time.

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