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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Straight Line
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The velocity-time graph of a moving body is shown in figure. The ratio of acceleration during interval OB and BC is

\[(a)\;1\quad (b)\; \frac{1}{2} \quad (c)\;\frac{1}{3} \quad (d)3\]

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In a velocity time graph the slope is the acceleration of the body during the given interval
$\large\frac{acceleration \;during\;OB}{acceleration\;during \;BC}=\frac{\tan 30}{\tan 60}=\frac{1/\sqrt 3}{\sqrt 3}=\frac{1}{3}$
Hence c is the correct answer. 


answered Jun 24, 2013 by meena.p
edited Jan 24, 2014 by meena.p

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