logo

Ask Questions, Get Answers

X
 
Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Motion in a Straight Line

The velocity-time graph of a moving body is shown in figure. The ratio of acceleration during interval OB and BC is

\[(a)\;1\quad (b)\; \frac{1}{2} \quad (c)\;\frac{1}{3} \quad (d)3\]

1 Answer

In a velocity time graph the slope is the acceleration of the body during the given interval
$\large\frac{acceleration \;during\;OB}{acceleration\;during \;BC}=\frac{\tan 30}{\tan 60}=\frac{1/\sqrt 3}{\sqrt 3}=\frac{1}{3}$
Hence c is the correct answer. 

 

answered Jun 24, 2013 by meena.p
edited Jan 24, 2014 by meena.p
 

Related questions

...