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# A car travelling with a speed of 60 km/hr can brake to stop within a distance of 20m. If the car is going twice as fast, the stopping distance will be ?

$(a)\;20 m\quad (b)\;40 m \quad (c)\;60 m \quad (d)80 m$

$v^2-u^2=2as$
$0=u^2+2(-a)s$
$s =\; u^2$/2a
Since speed is doubled, the distance becomes 4 times
Hence d is the correct answer.
edited May 23, 2014