a)160 m and 100 m

b)80 m and 20 m

c)20 m and 80 m

d)100 m and 160 m

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Time taken by first ball h reach the ground

$=\sqrt {\large\frac{2H}{g}}=\sqrt {\large\frac{2 \times 180}{10}}$$=6 sec$

time interval between two balls in 2 seconds

$H_1=\large\frac{1}{2} $$g(4)^2=80 m$

$H_1=\large\frac{1}{2} $$g(2)^2=20 m$

Height from ground are $180-80=100m$

$180 -20 =160 m$

Hence d is the correct answer.

Meena ji..i'm confused..where is the value of u in the equations of H1 and H2..? Pls reply.

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