\[(a)\; 30 ^{\circ}\quad (b)\;45 ^{\circ} \quad (c)\;60^{\circ} \quad (d)90^{\circ}\]

$S=\large\frac{1}{2} g$$ \sin \theta (2t)^2$ and $\large\frac{h}{s}$$=\sin \theta$

$\large\frac{h}{\sin \theta}=\large\frac{1}{2}$$ g \sin \theta (2t)^2$

Also since 't' is time taken to fall h height of h.

$h=\large\frac{1}{2}$$gt^2$

$\large\frac{\Large\frac{1}{2}gt^2}{\sin \theta}=\frac{1}{2} $$\;g \sin \theta\; 4t^2$

$\sin ^2 \theta=\large\frac{1}{4}$$=>\theta=30 ^{\circ}$

Hence a is the correct answer.

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