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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Straight Line
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A ball is dropped vertically from a height 'd' above the ground. it hits the ground and bounces up vertically to a height $d/2$ neglecting air resistance its velocity 'v' varies with height 'h' above the ground as


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The graph between h and v will be a parabola. At $h = d $ , velocity is zero,
( Taking downward direction as negative)
Then its negetive value increases , and at $h =0$ velocity gets reversed and then goes on decreasing and becomes zero at $h = d/2$
Hence a is the correct answer.


answered Jun 24, 2013 by meena.p
edited Jan 25, 2014 by meena.p

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