\[(a)\; 50 m \quad (b)\;80 m \quad (c)\;120 m \quad (d)100 m \]

The body falls through

$h-\bigg(\large\frac{7h}{16} \bigg)=\frac{9h}{16}$ during $(n-1)$ seconds and fall through 'h' in n seconds

using $s=ut+\large\frac{1}{2}$$ at ^2 $

$\large\frac{9h}{16}$$=5(n-1)^2$

and $h=5n^2$

dividing $\large\frac{9}{16}=\frac{(n-1)^2}{n^2}$

we get $ n=4$

Therefore $ h=5 \times 4^2=80 m$

Hence b is the correct answer.

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