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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Motion in a Straight Line

A particle starts from rest at $t=0$ and undergoes an acceleration 'a' in $m/s^2$ with 't' in sec as shown

Which of the following represents velocity v in m/s and time t in seconds

 

1 Answer

For interval 0 to 2 sec
$u=0\;a=3\;t=2$
$v=u+at=6 m/s$
for $2\; to \;4s$
$a=-3,\;u=6,\;t=2$
$v'=+6+(-3) \times 2=0$
Hence a is the correct answer.

 

answered Jun 25, 2013 by meena.p
edited Jan 25, 2014 by meena.p
 

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