Browse Questions

# Time taken to reach A to B for a projectile is 't'. Then the distance AB is equal to

$a)\;\large\frac{ut}{\sqrt 3} \\ b)\;\large\frac{\sqrt 3 ut}{2}\\ c)\;\sqrt ut \\ d)\;2 ut$

Horizontal component of u is $u \cos 60$
$=\large\frac{u}{2}$