logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Plane
0 votes

Time taken to reach A to B for a projectile is 't'. Then the distance AB is equal to

 

$ a)\;\large\frac{ut}{\sqrt 3} \\ b)\;\large\frac{\sqrt 3 ut}{2}\\ c)\;\sqrt ut \\ d)\;2 ut$

Can you answer this question?
 
 

1 Answer

0 votes
Horizontal component of u is $u \cos 60$
$=\large\frac{u}{2}$
$AC=\large\frac{u}{2}$$t=\large\frac{ut}{2}$
$AB=AC \sec 30$
$\qquad=\large\frac{ut}{2} \frac{2}{\sqrt 3}$
$\qquad=\large\frac{ut}{\sqrt 3}$
Hence a is the correct answer.

 

answered Jun 26, 2013 by meena.p
edited Jan 25, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...