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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Motion in a Plane

Time taken to reach A to B for a projectile is 't'. Then the distance AB is equal to

 

$ a)\;\large\frac{ut}{\sqrt 3} \\ b)\;\large\frac{\sqrt 3 ut}{2}\\ c)\;\sqrt ut \\ d)\;2 ut$

1 Answer

Horizontal component of u is $u \cos 60$
$=\large\frac{u}{2}$
$AC=\large\frac{u}{2}$$t=\large\frac{ut}{2}$
$AB=AC \sec 30$
$\qquad=\large\frac{ut}{2} \frac{2}{\sqrt 3}$
$\qquad=\large\frac{ut}{\sqrt 3}$
Hence a is the correct answer.

 

answered Jun 26, 2013 by meena.p
edited Jan 25, 2014 by meena.p
 

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