logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Straight Line
0 votes

A man moves along x axis such that velocity $v=\large\frac{1}{x}$. If he is initially at $x=2 m$ find the time when he reaches $x=4m$

\[(a)\;6 sec\quad (b)\;4 sec \quad (c)\;3 sec \quad (d)\;he\;can't\;reach\; x=4m\]

Can you answer this question?
 
 

1 Answer

0 votes
We have $v=\large\frac{dx}{dt}$
Therefore $\large\frac{1}{x}=\frac{dx}{dt}$
$\int dt=\int x dx$
$ t= \large \frac{x^2}{2} \bigg|_2^4$
$=>t=6\;sec$
Hence a is the correct answer.

 

answered Jun 28, 2013 by meena.p
edited Jan 25, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...