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Home  >>  CBSE XII  >>  Math  >>  Application of Integrals
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Choose the correct answer in the area of the region bounded by the curve \(y^2 = 4x\), \(y\) - axis and the line \(y = 3\) is

 \[ (A) 2   \quad  (B) \frac{9}{4}   \quad  (C) \frac{9}{3}   \quad  (D) \frac{9}{5}\]
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  • The area bounded by the curve g(y),y axis and the ordinate y=c,y=d is given by,\[A=\int_c^dx\;dy=\int_c^dg(y)\;dy.\]
Hence the area of the region bounded by the curve $y^2=4x$,y-axis and the line y=3 is the shaded portion as shown in the fig.
Hence $A=\int_0^3x\;dy.$
Here $x=\frac{y^2}{4}$
$A=\int_0^3\frac{y^2}{4}\;dy.$
On integrating we get,
$A=\frac{1}{4}\begin{bmatrix}\frac{y^3}{3}\end{bmatrix}_0^3$.
On applying limits we get,
$A=\frac{1}{12}[3^3-0]$
$\;\;\;\;=\frac{1}{12}\times 27=\frac{9}{4}$sq.units.
Hence B is the correct answer.
answered Dec 20, 2013 by yamini.v
 

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