+91-9566306857  (or)  +91-9176170648

Ask Questions, Get Answers

Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11

A ball $B_1$ is projected from A at a velocity u making an angle $30 ^{\circ}$with the horizontal. Another ball $B_2$ is simultaneously projected from C verically up and with velocity v.Both collide each other at their maximum heights. What is ratio $\large\frac{u}{v}$

$a)\;4 \\b)\;2 \\c)\;1 \\ d)\;0.5 $

1 Answer

For Ball $B_2 : 0-v^2=-2gh$
For Ball $B_1$ to reach the same height the vertical component of velocity is $u \sin \theta=u \sin 30$
$\quad \qquad= u/2$
Therefore $\large\frac{-u^2}{4}$$=-2g\bigg(\large\frac{v^2}{2g}\bigg)$
Hence b is the correct answer.
answered Jun 28, 2013 by meena.p
edited May 24, 2014 by lmohan717

Related questions