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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11
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Q)

A point moves in $X-Y$ plane according to $X=4 \sin \;6t $ and $Y=4(1-\cos \;6t)$.The distance traversed by the particle in 4 seconds is (x and y are in meters)

\[(a)\;96 m \quad (b)\;48 m \quad (c)\;24 m \quad (d)\;108 m\]

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