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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11
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Q)

A particle moves in xy plane. The position vector of particle at any time t is $\overrightarrow r=\{(2t) i+(2t^2)j\}\; m$. The rate of change of $\theta$ at time $t= 2\;$ seconds is ( $\theta$ is the angle which its velocity vector makes with positive x-axis )

\[(a)\;\frac{2}{17}rad/s\quad (b)\;\frac{1}{14}rad/s \quad (c)\;\frac{4}{7}rad/s \quad (d)\;\frac{6}{5}rad/s\]

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