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Velocity versus displacement graph of a particle moving in a straight line is shown. corresponding acceleration versus velocity graph will be

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From the given graph we get that $\large\frac{dv}{ds}$$=1 s^{-1}(a \;constant)$
Also $v=\large\frac{ds}{dt}$
and $a=\large\frac{dv}{dt}$
$\quad a=\large\frac{dv}{ds}$$.v$
$\quad a=v$
Since $\large\frac{dv}{ds}$$=1$
Therefore acceleration versus velocity graph is a straight line passing through orgin with slope $1s^{-1}$
Hence a is the correct answer.
answered Jul 1, 2013 by meena.p
edited May 24, 2014 by lmohan717

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