From the given graph we get that $\large\frac{dv}{ds}$$=1 s^{-1}(a \;constant)$

Also $v=\large\frac{ds}{dt}$

=>$dt=\large\frac{ds}{v}$

and $a=\large\frac{dv}{dt}$

$\quad a=\large\frac{dv}{ds}$$.v$

$\quad a=v$

Since $\large\frac{dv}{ds}$$=1$

Therefore acceleration versus velocity graph is a straight line passing through orgin with slope $1s^{-1}$

Hence a is the correct answer.

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