logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11
0 votes

Velocity versus displacement graph of a particle moving in a straight line is shown. corresponding acceleration versus velocity graph will be

Can you answer this question?
 
 

1 Answer

0 votes
From the given graph we get that $\large\frac{dv}{ds}$$=1 s^{-1}(a \;constant)$
Also $v=\large\frac{ds}{dt}$
=>$dt=\large\frac{ds}{v}$
and $a=\large\frac{dv}{dt}$
$\quad a=\large\frac{dv}{ds}$$.v$
$\quad a=v$
Since $\large\frac{dv}{ds}$$=1$
Therefore acceleration versus velocity graph is a straight line passing through orgin with slope $1s^{-1}$
Hence a is the correct answer.
answered Jul 1, 2013 by meena.p
edited May 24, 2014 by lmohan717
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...