# Velocity versus displacement graph of a particle moving in a straight line is shown. corresponding acceleration versus velocity graph will be

From the given graph we get that $\large\frac{dv}{ds}$$=1 s^{-1}(a \;constant) Also v=\large\frac{ds}{dt} =>dt=\large\frac{ds}{v} and a=\large\frac{dv}{dt} \quad a=\large\frac{dv}{ds}$$.v$
$\quad a=v$
Since $\large\frac{dv}{ds}$$=1$
Therefore acceleration versus velocity graph is a straight line passing through orgin with slope $1s^{-1}$
Hence a is the correct answer.
edited May 24, 2014