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There are two values of time for which a projectile is at same height. The sum of these two times is
\[(a)\;\frac{3T}{2}\quad (b)\;\frac{4T}{3} \quad (c)\;\frac{3T}{4} \quad (d)\;T\]
jeemain
physics
class11
unit2
kinematics
q71
easy
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asked
Jul 1, 2013
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meena.p
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Aug 11, 2014
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1 Answer
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Time taken to go from $O \;to\; A=t_1$
Time taken to go from $O \;to\; B=t_2$
Also we have time taken to go from $O \;to\; A$=Time taken to go from $B \;to\; D$
Therefore $ t_1+t_2=t_2$+ time taken to go from $B \;to\; D$
$\qquad=T$
Hence d is the correct answer.
answered
Jul 1, 2013
by
meena.p
edited
Jan 26, 2014
by
meena.p
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