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A particle is released from rest from a tower of height 3h, the ratio of time of fall for equal heights h ie $t_1:t_2:t_3$ is

\[(a)\;\sqrt 3:\sqrt 2:1 \quad (b)\;3:2:1 \quad (c)\;9:4:1 \quad (d)\;1:(\sqrt 2-1):(\sqrt 3-\sqrt 2)\]

1 Answer

$t_1 :(t_1+t_2):(t_1+t_2+t_3)=1 : \sqrt 2:\sqrt 3$
or $t_1 :t_2:t_3=1:(\sqrt 2-1):(\sqrt 3-\sqrt 2)$
Hence d is the correct answer.


answered Jul 1, 2013 by meena.p
edited Jan 26, 2014 by meena.p

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