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Home  >>  CBSE XII  >>  Math  >>  Integrals
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Evaluate the definite integral\[\int\limits_2^3\frac{1}{x}dx\]

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Toolbox:
  • (i)$\int\limits_a^b f(x)dx= F(b)-F(a)$
  • (ii)$\int \frac{1}{x}dx=log x$
Given $I=\int \limits_2^3 \large\frac{1}{x}dx$
 
On integrating we get,
 
[log x]
 
On applying limits we get,
 
$ I= log3-log2$
 
But we know $log a-log b=log|a/b|,$ similarly
 
$ I=log 3/2$

 

answered Feb 10, 2013 by meena.p
 
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