In millikan oil drop experiment a charged drop falls with a terminal velocity V. If an electric field E is applied vertically upwards it moves with terminal velocity 2V in upward direction. If electric field reduces to E/2 then its terminal velocity will be -

Question

( A ) $\frac{v}{2}$
( B ) $\frac{3v}{2}$
( C ) ${2v}$
( D ) ${v}$