\[(a)\;5 \sqrt 3\; m/s^2 \quad (b)\;5\; m/s^2 \quad (c)\;10\; m/s^2 \quad (d)\;2.5\; m/s^2\]

Answer: 5 m/s$^2$

Rate change of speed, $\large\frac{dv}{dt}$$=$ tangential acceleration $=\large\frac{\text{tangential force}}{\text{mass}}$

When $\theta=30^{\circ}$, tangential force is $mg\; \sin \theta$

Therefore $a=\large\frac{mg \sin 30}{m}$

$\qquad\qquad=10 \sin 30$

$\qquad\qquad=10 \times \frac{1}{2}$

$\qquad\qquad=5 m/s^2$

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