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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  1999
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According to hardy Schultze law the order of coagulation power of cations will be :


( A ) $Al^{+3} > {Na^{+}} > Ba^{+2}$
( B ) $Ba^{+2 } > {Al^{+3}} > {Na^{+}}$
( C ) ${Na^{+}} > Ba^{+2} > {Al^{+3}}$
( D ) ${Al^{3+}}>{Ba^{2+}}>{Na^{+}}$

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