\[(a)\;\frac{u^2\cos \alpha}{2g} \quad (b)\;\frac{u^2\sin \alpha}{2g}\quad (c)\;\frac{u^2}{g} \quad (d)\;\frac{u^2}{2g}\]

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

The two angles of projection which the horizontal range is same are $\alpha$ and $90-\alpha$

$H_1=\large\frac{u^2 \sin ^ 2 \alpha}{2g}$

$H_2=\large\frac{u^2 \sin ^ 2 (90-\alpha)}{2g}$

$\qquad=\large\frac{u^2 \cos^2 \alpha}{2g}$

$H_1+H_2=\large\frac{u^2}{2g}$$(\sin ^2 \alpha+\cos ^2 \alpha)$

$\qquad=\large\frac{u^2}{2g}$

Hence d is the correct answer.

Ask Question

Take Test

x

JEE MAIN, CBSE, AIPMT Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...