logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Plane
0 votes

A particle moves in the plane according to the law $x=kt$, $y=kt(1- \alpha t)$ where $k$ and $\alpha$ are positive constants, t is time. The particle trajectory $ y(x) $ is

a) circle b) parabola c) straight line d) hyperbola

Can you answer this question?
 
 

1 Answer

0 votes
$x=kt,y=kt(1-\alpha t)$
$y=kt-k\alpha t^2$
$y=x-k\; \alpha \;t^2$
$y=x-k \;\alpha\;\large\frac{x^2}{k^2}$
ie parabola
Hence b is the correct answer.

 

answered Jul 2, 2013 by meena.p
edited Jan 26, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...