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Two diamonds begin a free fall from rest from same height $1.0 \; sec$ apart How long after will the two diamonds be 10 m apart ? $(g=10 m/s)$

\[(a)\;2\;sec \quad (b)\;1.5 \;sec \quad (c)\;1\;sec \quad(d)\;2.5 \;sec \]

1 Answer

We have
$\large\frac{1}{2}$$ \times gt^2-\large\frac{1}{2}$$ g(t-1)^2=10$
$t=1.5 \;sec$
Hence b is the correct answer. 


answered Jul 2, 2013 by meena.p
edited Jan 26, 2014 by meena.p

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