\[(a)\;90\; m \quad (b)\;45 \;m \quad (c)\;35 \;m \quad(d)\;25\; m \]

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Let height of tower be 'h'

Time taken for 1st stone to reach ground is $=\sqrt {\large\frac{2h}{g}}$

$\bigg[s=ut+\large\frac{1}{2}$$gt^2$$; h=\large\frac{1}{2} $$gt^2\bigg]$

Time taken for the first stone to be travel 5 m from top $=\sqrt {\large\frac{2 \times 5}{g}}$

Time taken for 2nd stone to reach ground from a point $(h-25)m$ above the ground is $\sqrt {\large\frac{2(h-25)}{g}}$

Therefore $ \sqrt {\large\frac{2h}{g}}-\sqrt {\large\frac{2 \times 5}{g}}=\sqrt {\large\frac{2(h-25)}{g}}$

$\sqrt {2h}-\sqrt {10}=\sqrt {2(h-25)}$

Solving we get $h=45 \;m$

Hence b is the correct answer.

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