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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Motion in a Plane
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The path followed by a body projected along y axis is given by $y=\sqrt 3 x-\large\frac{1}{2}$$ x^2$. If $g=10 m/s^2$ Then initial velocity of projectile is

\[(a)\;3 \sqrt {10} \; m/s \quad (b)\;2 \sqrt {10} \;m/s \quad (c)\;10 \sqrt {3} \;m/s \quad(d)\;10 \sqrt {2} \; m/s \]

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