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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Plane
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Distance between frog and an insect on a horizontal plane is 10m. Frog can jump with maximum speed of $\sqrt {10}m/s$ minimum number of jumps required by the frog to catch the insect is

\[(a)\;5 \quad (b)\;10 \quad (c)\;100 \quad(d)\;50 \]

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1 Answer

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For, minimum number of jumps, range has to be maximum.
Maximum range $ \large\frac{u^2}{g}= \frac{(\sqrt {10})^2}{10}$$=1m$
Total distance =$10 m$
number of jumps =10
Hence b is the correct answer.
answered Jul 3, 2013 by meena.p
edited Apr 2, 2014 by balaji.thirumalai

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