If the ball hits the $n^{th}$ step vertical distance travelled in $nh$ horizontal distance travelled is $nb$

Let $t$ be the time of fall

Initaial vertical velocity $=0$

Therefore $nb=ut$----(1)

$nh=0+\large\frac{1}{2}$$gt^2$-----(2)

from (1) and (2)

$n= \large\frac{2hu^2}{gb^2}$

Hence d is the correct answer.

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