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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Laws of Motion

A man of weight 1 mg is moving up in a rocket with an acceleration 4g. The apparent weight of the man in the rocket is

\[(a)\;zero \quad (b)\;4\;mg \quad (c)\;5\;mg \quad(d)\;mg \]

1 Answer

The apparent weight in a non inertial frame moving up with an acceleation 4g is
$R=m(g+a)$
$\quad=m(g+4g)$
$\quad=5\; mg$
Hence d is the correct answer.

 

answered Jul 4, 2013 by meena.p
edited Jan 26, 2014 by meena.p
 

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