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# A man pushes a truck initially at rest and weighting $2.5$ tonne along a horizontal rail with a steady force of $200 N$. The resistance to the motion amounts to $30 N$ per tonne. The velocity of the truck at the end of 30 seconds is

$(a)\;1.5 m/s \quad (b)\;0.15 m/s \quad (c)\;15 m/s \quad(d)\;150 m/s$
Can you answer this question?

Total resistance offered $=\large\frac{30 N}{tonne} $$\times 2.5 \;tonne \qquad=75 N Resultant force = 200-75=125 N mass =2.5 tonne=2500 kg a=\large\frac{F}{m}=\frac{125}{2500}=\frac{1}{20}$$m/s^2$
$v=u+at =0+\large\frac{1}{20}$$\times 30$
$\quad= 1.5 m/s$
Hence a is the correct answer

answered Jul 4, 2013 by
edited Jan 26, 2014 by meena.p