Total resistance offered $=\large\frac{30 N}{tonne} $$\times 2.5 \;tonne$

$\qquad=75 N$

Resultant force $= 200-75=125 N$

mass $=2.5 tonne=2500 kg$

$a=\large\frac{F}{m}=\frac{125}{2500}=\frac{1}{20} $$m/s^2$

$v=u+at =0+\large\frac{1}{20} $$\times 30$

$\quad= 1.5 m/s$

Hence a is the correct answer